Wein’s law is temperature (Kelvin) equals constant divided by peak wavelength (angstroms) [t=σ÷w]6000= σ ÷ 4830σ =28,980,000(L=luminosity) HD33278T=6740 K; L=1.372HD 124320T=7068 K; L=1.439HD 31084T=6440 K; L=1.311HD 242908T=6300 K; L=1.283SAO 76803T= 4912 K; L=1FEIGE 40T= 7245 K; L=1.4754 significant figures are necessary.
J=σT^4HD 33278J= 5.98e22 Ratio=3.54HD 124320J= 7.23e22 Ratio=4.28HD 31084J= 4.98e22 Ratio=2.95HD 242908J= 4.57e22 Ratio=2.7SAO 76803J= 1.69e22 Ratio=1FEIGE 40J= 7.98e22 Ratio=4.72
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Weins lawTemp (k) = constant/peak wavelength (angstroms) HD: 33278Temp= 4400kHD: 124320Temp= 4000kHD: 31084Temp= 4600kHD: 242908Temp= 3600kSAO: 76803Temp= 5800kFEIGE: 40Temp= 3800k
Wein's Law Temp(K)=constant/Max wavelength(A)HD: 33278Temp=6700kHD:12430Temp=7500kHD:31084Temp=6700kHD:242908Temp=8100kSAO:76803Temp=4500kFEIGE:40Temp=7700k
weins law temp(k)=constant/peak wavelength(a) HD 33278 Temp=4300k HD 124320 Temp=4100k HD 31084 Temp=4200k HD 242908 Temp=3700k HD76803 Temp=6700kHD 40TEMP=3900K
Energy of StarOT^45.67*10^-8 * 2.01*10^15= 11.40*10^75.67*10^-8 * 3.16*10^15= 17.92*10^75.67*10^-8 * 2.01*10^15= 11.40*10^75.67*10^-8 * 4.30*10^15= 24.38*10^75.67*10^-8 * 4.10*10^14= 23.25*10^65.67*10^-8 * 3.52*10^15= 19.96*10^7
The Stefan-Boltzmann Radiation Law E=σT^41. E= (5.67x10^-8)(4400)^4E= 21251704.322. E= (5.67x10^-8)(4000)^4E= 145152003. E=(5.67x10^-8)(4600)^4E= 25387175.524. E=(5.67x10^-8)(3600)^4E= 9523422.725. E=(5.67x10^-8)(5800)^4E= 64164532.326. E=(5.67x10^-8)(3800)^4E= 11822721.12
1-1.9X10^152-1.6X10^153-1.7X10^154-1.0X10^155-1.1X10^166-1.3X10^15
Wein’s law is temperature (Kelvin) equals constant divided by peak wavelength (angstroms) [t=σ÷w]
ReplyDelete6000= σ ÷ 4830
σ =28,980,000
(L=luminosity)
HD33278
T=6740 K; L=1.372
HD 124320
T=7068 K; L=1.439
HD 31084
T=6440 K; L=1.311
HD 242908
T=6300 K; L=1.283
SAO 76803
T= 4912 K; L=1
FEIGE 40
T= 7245 K; L=1.475
4 significant figures are necessary.
J=σT^4
DeleteHD 33278
J= 5.98e22 Ratio=3.54
HD 124320
J= 7.23e22 Ratio=4.28
HD 31084
J= 4.98e22 Ratio=2.95
HD 242908
J= 4.57e22 Ratio=2.7
SAO 76803
J= 1.69e22 Ratio=1
FEIGE 40
J= 7.98e22 Ratio=4.72
This comment has been removed by the author.
ReplyDeleteWeins law
ReplyDeleteTemp (k) = constant/peak wavelength (angstroms)
HD: 33278
Temp= 4400k
HD: 124320
Temp= 4000k
HD: 31084
Temp= 4600k
HD: 242908
Temp= 3600k
SAO: 76803
Temp= 5800k
FEIGE: 40
Temp= 3800k
Wein's Law
ReplyDeleteTemp(K)=constant/Max wavelength(A)
HD: 33278
Temp=6700k
HD:12430
Temp=7500k
HD:31084
Temp=6700k
HD:242908
Temp=8100k
SAO:76803
Temp=4500k
FEIGE:40
Temp=7700k
weins law
ReplyDeletetemp(k)=constant/peak wavelength(a)
HD 33278
Temp=4300k
HD 124320
Temp=4100k
HD 31084
Temp=4200k
HD 242908
Temp=3700k
HD76803
Temp=6700k
HD 40
TEMP=3900K
Energy of Star
ReplyDeleteOT^4
5.67*10^-8 * 2.01*10^15= 11.40*10^7
5.67*10^-8 * 3.16*10^15= 17.92*10^7
5.67*10^-8 * 2.01*10^15= 11.40*10^7
5.67*10^-8 * 4.30*10^15= 24.38*10^7
5.67*10^-8 * 4.10*10^14= 23.25*10^6
5.67*10^-8 * 3.52*10^15= 19.96*10^7
This comment has been removed by the author.
ReplyDeleteThis comment has been removed by the author.
DeleteThis comment has been removed by the author.
ReplyDeleteThe Stefan-Boltzmann Radiation Law E=σT^4
ReplyDelete1. E= (5.67x10^-8)(4400)^4
E= 21251704.32
2. E= (5.67x10^-8)(4000)^4
E= 14515200
3. E=(5.67x10^-8)(4600)^4
E= 25387175.52
4. E=(5.67x10^-8)(3600)^4
E= 9523422.72
5. E=(5.67x10^-8)(5800)^4
E= 64164532.32
6. E=(5.67x10^-8)(3800)^4
E= 11822721.12
1-1.9X10^15
ReplyDelete2-1.6X10^15
3-1.7X10^15
4-1.0X10^15
5-1.1X10^16
6-1.3X10^15