Monday, May 7, 2012

Module 6

State the B-v, the absolute and apparent magnitudes and the distance in parsecs and light years for each of your 3 stars.
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4 comments:

  1. Paul (˚д˚)May 8, 2012 at 9:24 AM

    HD 331055
    B-v = 0.58
    Absolute Magnitude (M) = 10.39
    Apparent Magnitude (m) = 3.8
    Distance (pc) = 207.9696687
    Distance (ly) = 678.3063382

    HD 331057
    B-v = 0
    Absolute Magnitude (M) = 9.2
    Apparent Magnitude (m) = 0.7
    Distance (pc) = 501.1872336
    Distance (ly) = 1634.654127

    HD 3310554
    B-v = 0.94
    Absolute Magnitude (M) = 8.91
    Apparent Magnitude (m) = 3.8
    Distance (pc) = 105.1961874
    Distance (ly) =343.1040742

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  2. DeEttaMay 8, 2012 at 9:24 AM

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  3. DeEttaMay 8, 2012 at 9:30 AM

    d=10^0.2(m-M+5)

    1.
    B=11.30
    V=10.73
    B-V=1.63
    Mv=9
    D=22.18 parsecs
    D=72.31 Light years

    2.
    B =9.00
    V =9.00
    B-V=0
    Mv=0.1
    D=602.56 parsecs
    D=1964.35 Light years

    3.
    B =9.58
    V =9.59
    B-V=0.01
    Mv=3
    D=2.52 parsecs
    D=8.22 Light years

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  4. AnonymousMay 10, 2012 at 9:08 AM

    d=10^.2(m-M+5) m
    V B B-V M

    10- hd331054 8.91 9.85 .94 7
    13- hd331072 10.17 11.7 1.53 10
    12- hd332087 9.18 9.53 .35 3

    10- hd331054 d=10^.2(8.91-7+5)
    d=10^.2(6.91)
    d=10^1.382
    d=24.1parscc
    24.1*3.26= 78.6 light yrs

    13- hd331072 d=10^.2(10.17-10+5)
    d=10^.2(5.17)
    d=10^1.034
    d=10.8 parscc
    10.8*3.26= 35.2 light yrs

    12- hd332087 d=10^.2(9.18-3+5)
    d=10^.2(11.18)
    d=10^2.236
    d=172.2 parscc
    172.2*3.26= 561.4 light yrs

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